(x-y)(x^2+5xy+y^2)=0

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Solution for (x-y)(x^2+5xy+y^2)=0 equation: 


Simplifying
(x + -1y)(x2 + 5xy + y2) = 0

Reorder the terms:
(x + -1y)(5xy + x2 + y2) = 0

Multiply (x + -1y) * (5xy + x2 + y2)
(x(5xy + x2 + y2) + -1y * (5xy + x2 + y2)) = 0
((5xy * x + x2 * x + y2 * x) + -1y * (5xy + x2 + y2)) = 0

Reorder the terms:
((xy2 + 5x2y + x3) + -1y * (5xy + x2 + y2)) = 0
((xy2 + 5x2y + x3) + -1y * (5xy + x2 + y2)) = 0
(xy2 + 5x2y + x3 + (5xy * -1y + x2 * -1y + y2 * -1y)) = 0
(xy2 + 5x2y + x3 + (-5xy2 + -1x2y + -1y3)) = 0

Reorder the terms:
(xy2 + -5xy2 + 5x2y + -1x2y + x3 + -1y3) = 0

Combine like terms: xy2 + -5xy2 = -4xy2
(-4xy2 + 5x2y + -1x2y + x3 + -1y3) = 0

Combine like terms: 5x2y + -1x2y = 4x2y
(-4xy2 + 4x2y + x3 + -1y3) = 0

Solving
-4xy2 + 4x2y + x3 + -1y3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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